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- // Copyright 2005, Google Inc.
- // All rights reserved.
- //
- // Redistribution and use in source and binary forms, with or without
- // modification, are permitted provided that the following conditions are
- // met:
- //
- // * Redistributions of source code must retain the above copyright
- // notice, this list of conditions and the following disclaimer.
- // * Redistributions in binary form must reproduce the above
- // copyright notice, this list of conditions and the following disclaimer
- // in the documentation and/or other materials provided with the
- // distribution.
- // * Neither the name of Google Inc. nor the names of its
- // contributors may be used to endorse or promote products derived from
- // this software without specific prior written permission.
- //
- // THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS
- // "AS IS" AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT
- // LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR
- // A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT
- // OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL,
- // SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT
- // LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
- // DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
- // THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
- // (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE
- // OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
- // A sample program demonstrating using Google C++ testing framework.
- #include "sample1.h"
- // Returns n! (the factorial of n). For negative n, n! is defined to be 1.
- int Factorial(int n) {
- int result = 1;
- for (int i = 1; i <= n; i++) {
- result *= i;
- }
- return result;
- }
- // Returns true iff n is a prime number.
- bool IsPrime(int n) {
- // Trivial case 1: small numbers
- if (n <= 1) return false;
- // Trivial case 2: even numbers
- if (n % 2 == 0) return n == 2;
- // Now, we have that n is odd and n >= 3.
- // Try to divide n by every odd number i, starting from 3
- for (int i = 3; ; i += 2) {
- // We only have to try i up to the square root of n
- if (i > n/i) break;
- // Now, we have i <= n/i < n.
- // If n is divisible by i, n is not prime.
- if (n % i == 0) return false;
- }
- // n has no integer factor in the range (1, n), and thus is prime.
- return true;
- }
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